Last updated at May 29, 2018 by Teachoo

Transcript

Ex 13.1,9 A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in figure. If the height of the cylinder is 10 cm, and its base is of radius 3.5 cm, find the total surface area of the article. Total surface area of article = Curved surface area of cylinder + 2 × Curved surface area of hemisphere Curved surface area of cylinder Radius = r = 3.5 cm Height of the cylinder = h = 10 cm Curved surface area of cylinder = 2πrh = 2 ×22/7×3.5× 10 = 2 × 22/7×35 = 2 × 22 × 5 = 220 cm2 Surface area of hemisphere Radius of hemisphere = r = 3.5 cm Surface area of hemisphere = 2πr2 = 2×22/7×(3.5)^2 = 2×22/7×3.5×3.5 = 2×22×0.5×3.5 = 44 ×0.5×3.5 = 77 cm2 Surface area of 2 hemisphere = 2 ×"Surface area of hemisphere" = 2 ×77 = 154 cm2 Total surface area of article = Curved surface area of cylinder + 2 × Curved surface area of hemisphere = 220 + 154 = 374 cm2 Hence , Total surface area of article = 374 cm2

Example 2
Important

Example 3 Important

Ex 13.1, 4 Important

Ex 13.1, 9 Important You are here

Example 6 Important

Example 7 Important

Example 9 Important

Example 11 Important

Ex 13.3, 8 Important

Ex 13.3, 9 Important

Example 12 Important

Ex 13.4, 4 Important

Ex 13.4, 5 Important

Surface Area and Volume Formulas Important

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.