Check sibling questions

Ex 13.3, 9 - A farmer connects a pipe of diameter 20 cm - Conversion of one shape to another

Ex 13.3, 9 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2
Ex 13.3, 9 - Chapter 13 Class 10 Surface Areas and Volumes - Part 3
Ex 13.3, 9 - Chapter 13 Class 10 Surface Areas and Volumes - Part 4

This video is only available for Teachoo black users


Transcript

Ex 13.3, 9 A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in her field, which is 10 m in diameter and 2 m deep. If water flows through the pipe at the rate of 3 km/h, in how much time will the tank be filled? Let length of pipe for filling whole tank be h m. So, Volume of pipe = Volume of tank Volume of pipe Pipe is in form of cylinder where Let Height = h m Diameter = 20 cm So, radius = π‘‘π‘–π‘Žπ‘šπ‘’π‘‘π‘’π‘Ÿ/2 = 20/2 = 10 cm = 10 Γ— 1/100 m = 1/10 m Volume of pipe = Volume of cylinder = πœ‹r2h = πœ‹(1/10)^2 h = πœ‹ Γ— 1/100 Γ— h = πœ‹β„Ž/100 Volume of tank Tank is in form cylinder where Diameter = 10 m Radius = r = 10/2 m = 5 m Height = h = 2 m Volume of tank = πœ‹r2h = πœ‹(5)^2 Γ— 2 = πœ‹ Γ— 25 Γ— 2 = 50πœ‹ Now, Volume of pipe = Volume of tank πœ‹β„Ž/100 = 50πœ‹ h = (50πœ‹ Γ—100 )/πœ‹ h = 5000 m h = 5 km Now, Water in pipe flows at rate 3 km/hr So, 3 km travels in pipe in = 1 hour 1 km travels in pipe in = 1/3 hr 5 km travels in pipe in = 5/3 hr = 5/3 Γ— 60 minutes = 5 Γ— 20 minutes = 100 minutes. So, in 100 minutes, the tank will be filled

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.