Question 21 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 13, 2024 by Teachoo

If 49x + 51y = 499, 51x + 49y = 501, then find the value of x and y.

[Class 10] If 49x + 51y = 499, 51x + 49y = 501, find value of x and y - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard

part 2 - Question 21 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 21 If 49x + 51y = 499, 51x + 49y = 501, then find the value of x and yGiven equations 49x + 51y = 499 51x + 49y = 501 Adding both equations (49x + 51y) + (51x + 49y) = 499 + 501 100x + 100y = 1000 100(x + y) = 1000 x + y = 10 Subtracting both equations (49x + 51y) − (51x + 49y) = 499 − 501 −2x + 2y = −2 2(−x + y) = −2 −x + y = −1 Adding (1) and (2) (x + y) + (−x + y) = 10 + (−1) 2y = 9 y = 𝟗/𝟐 Putting value of y in (1) x + y = 10 x + 𝟗/𝟐 = 10 x = 10 − 𝟗/𝟐 x = (20 − 9)/2 x = 𝟏𝟏/𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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