If the system of equations 3x + y = 1 and (2k – 1)x + (k – 1)y = 2k + 1
is inconsistent, then k =
(a) -1 (b) 0 (c) 1 (d) 2
 ![[MCQ] If the system of equations 3x + y = 1 and (2k-1)x +(k-1)y = 2k+1 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard](https://cdn.teachoo.com/a92130bc-6d8f-4b6b-b5aa-edfbd98fe068/slide8.jpg) 
 
 
  
 
CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
        
      
CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard
Last updated at December 13, 2024 by Teachoo
 ![[MCQ] If the system of equations 3x + y = 1 and (2k-1)x +(k-1)y = 2k+1 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard](https://cdn.teachoo.com/a92130bc-6d8f-4b6b-b5aa-edfbd98fe068/slide8.jpg) 
 
 
  
 
Transcript
Given equations 3x + y = 1 (2k – 1)x + (k – 1)y = 2k + 1 Now, Since equations are inconsistent It means that the lines are parallel 𝑎1/𝑎2 = 𝑏1/𝑏2 ≠ 𝑐1/𝑐2 𝟑/((𝟐𝒌 − 𝟏)) = 𝟏/((𝒌 − 𝟏)) ≠ 𝟏/((𝟐𝒌 + 𝟏)) Thus, 𝟑/((𝟐𝒌 − 𝟏)) = 𝟏/((𝒌 − 𝟏)) 3(k − 1) = (2k − 1) 3k − 3 = 2k − 1 3k − 2k = −1 + 3 k = 2 So, the correct answer is (d)