Learn all Concepts of Chapter 7 Class 10 (with VIDEOS). Check - Coordinate Geometry - Class 10

Example 13 - Find area of triangle P(–1.5, 3), Q(6, -2) - Area of triangle

  1. Chapter 7 Class 10 Coordinate Geometry
  2. Serial order wise

Transcript

Example 13 Find the area of the triangle formed by the points P( 1.5, 3), Q(6, 2) and R( 3, 4). Area of triangle PQR = 1/2 [ x1(y2 y3) + x2(y3 y1) + x3(y1 y2) ] Here x1 = 1.5 , y1 = 3 x2 = 6 , y2 = 2 x3 = 3 , y3 = 4 Putting values Area of triangle PQR = 1/2 [ ( 1.5)( 2 4) + 6(4 3 ) + ( 3)(3 ( 2)) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(3 + 2) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(5) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(5) ] = 1/2 [ 9 + 6 15 ] = 1/2 [ 0 ] = 0

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.