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Example 13 - Chapter 7 Class 10 Coordinate Geometry
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Example 13 Find the area of the triangle formed by the points P( 1.5, 3), Q(6, 2) and R( 3, 4). Area of triangle PQR = 1/2 [ x1(y2 y3) + x2(y3 y1) + x3(y1 y2) ] Here x1 = 1.5 , y1 = 3 x2 = 6 , y2 = 2 x3 = 3 , y3 = 4 Putting values Area of triangle PQR = 1/2 [ ( 1.5)( 2 4) + 6(4 3 ) + ( 3)(3 ( 2)) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(3 + 2) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(5) ] = 1/2 [ 1.5( 6) + 6(1) + ( 3)(5) ] = 1/2 [ 9 + 6 15 ] = 1/2 [ 0 ] = 0
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Chapter 7 Class 10 Coordinate Geometry
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.