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Ex 7.1 , 1 Find the distance between the following pairs of points : (i) (2, 3), (4, 1) Let the two points be P(2, 3) & Q(4, 1) We need to find distance PQ PQ = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) Here, x1 = x coordinate of P = 2 y1 = y coordinate of P = 3 x2 = x coordinate of Q = 4 y2 = y coordinate of Q = 1 Putting values PQ = √((4 −2 )2+(1 −3)2) = √((2 )2+(−2)2) = √((2 ×2)+(−2 ×−2) ) = √(4+4) = √8 = √(4(2)) = √(4 ×(2)) = √4 × √2 = 2 × √2 = 2√𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.