If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (−2, 5), then the coordinates of the other end of the diameter are

(A) (−6, 7)  

(B) (6, −7)

(C) (6, 7) 

(D) (−6, −7)

This question is simlar to Ex 7.2, 7 - Chapter 7 Class 10 Coordinate Geometry

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Question 1 If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (−2, 5), then the coordinates of the other end of the diameter are (A) (−6, 7) (B) (6, −7) (C) (6, 7) (D) (−6, −7) Let co-ordinates of A be (x, y) Since O (−2, 5) is mid-point of AB (−𝟐,𝟓)=((𝒙 + 𝟐)/𝟐,(𝒚 + 𝟑)/𝟐) Comparing x coordinates −2 = (𝑥 + 2)/2 (−2) × 2 = x + 2 −4 − 2 = x −6 = x x = −6 Comparing y coordinates 5 = (𝑦 + 3)/2 5 × 2 = y + 3 10 − 3 = y 7 = y y = 7 Thus, Coordinates of A = (x, y) = (−6, 7) So, the correct answer is (A)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.