The point on the x – axis which is equidistant from points (−1, 0) and (5, 0) is

(A) (0, 2) 

(B) (2, 0)

(C) (3, 0) 

D) (0, 3)

 

This question is similar to Ex 7.1, 7 - Chapter 7 Class 10 Coordinate Geometry

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Transcript

Question 3 The point on the x – axis which is equidistant from points (−1, 0) and (5, 0) is (A) (0, 2) (B) (2, 0) (C) (3, 0) (D) (0, 3) Let Given points be A (−1, 0) and B(5, 0) Since point is x- axis, it’s y- coordinate will be 0 So, let point be C(a, 0) Since, Point C is equidistant from A and B ∴ AC = BC √(( 𝑎−(−1)^2+(0−0)^2 ) = √(( 𝑎−5)^2+(0−0)^2 ) √(( 𝑎+1)^2+0^2 ) =√(( 𝑎−5)^2+0^2 ) √(𝑎^2+1^2+2(𝑎)(1)+0) =√(𝑎^2+5^2−2(𝑎)(5)+0) √(𝒂^𝟐+𝟏^𝟐+𝟐𝒂) =√(𝒂^𝟐+〖𝟐𝟓〗^𝟐−𝟏𝟎𝒂) Squaring both sides 𝑎^2+1+2𝑎=𝑎^2+25−10𝑎 1+2𝑎=25−10𝑥 2𝑎+10𝑎=25−1 12𝑎=24 𝑎=24/12 𝒂=𝟐 ∴ Required point is (2, 0) So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.