If P (2, 4), Q (0, 3), R (3, 6) and S (5, y) are the vertices of a parallelogram PQRS, then the value of y is

(A) 7 

(B) 5

(C) −7 

(D) −8

This question is simlar to Example 10 - Chapter 7 Class 10 Coordinate Geometry

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Question 5 If P (2, 4), Q (0, 3), R (3, 6) and S (5, y) are the vertices of a parallelogram PQRS, then the value of y is (A) 7 (B) 5 (C) βˆ’7 (D) βˆ’8 Since PQRS is a parallelogram It’s Diagonals bisect each other Therefore, Mid point of SQ = Mid point of PR ((0 + 5)/2,(3 + 𝑦)/2)=((2 + 3)/2,(4 + 6)/2) (5/2,(3 + 𝑦)/2)=(5/2,10/2) (5/2,(3 + 𝑦)/2)=(5/2,5) Since, we have to find value of y Comparing y-coordinate (3 + 𝑦)/2=5 3 + y = 5 Γ— 2 3 + y = 10 y = 10 βˆ’ 3 y = 7 So, the correct answer is (A)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.