Learn all Concepts of Chapter 7 Class 10 (with VIDEOS). Check - Coordinate Geometry - Class 10



Last updated at Dec. 8, 2016 by Teachoo
Transcript
Example 10 If the points A(6, 1), B(8, 2), C(9, 4) and D(p, 3) are the vertices of a parallelogram, taken in order, find the value of p. Let the points be A(6, 1) , B(8, 2) C(9, 4) , D(p, 3) We know that diagonals of parallelogram bisect each other So, O is the mid−pint of AC & BD ∴ We find x co−ordinate of O from both AC & BD Finding mid−point of AC, We have to find x co−ordinate of O x−coordinate of O = (𝑥1 + 𝑥2)/2 Where x1 = 6 , x2 = 9 , Putting values for x−coordinate x−coordinate of O = (6 + 9)/2 = 15/2 Finding mid−point of BD, We have to find x co−ordinate of O x−coordinate of O = (𝑥1 + 𝑥2)/2 Where x1 = 8 , x2 = p , Putting values for x−coordinate x−coordinate of O = (8+ 𝑝)/2 Comparing (1) & (2) 15/2 = (8+ 𝑝)/2 15 = 8 + p 15 = 8 + p 15 – 8 = p 7 = p p = 7 Hence, p = 7
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Example 5 Important
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Example 7
Example 8
Example 9 Important
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Example 11 Not in Syllabus - CBSE Exams 2021
Example 12 Not in Syllabus - CBSE Exams 2021
Example 13 Not in Syllabus - CBSE Exams 2021
Example 14 Important Not in Syllabus - CBSE Exams 2021
Example 15 Not in Syllabus - CBSE Exams 2021
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