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Example 12 Find the area of a triangle formed by the points A(5, 2), B(4, 7) and C (7, – 4). Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] Here x1 = 5 , y1 = 2 x2 = 4 , y2 = 7 x3 = 7 , y3 = −4 Putting values Area of triangle ABC = 1/2 [ 5(7 – (−4)) + 4(−4 – 2 ) + 7(2 − 7) ] = 1/2 [ 5(7 + 4) + 4(−6 ) + 7(−5) ] = 1/2 [ 5(11) + 4(−6 ) + 7(−5) ] = 1/2 [55 – 24 – 35 ] = 1/2 [−4] = −2 Since, Area cannot be negative Area of triangle ABC = 2 square units

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.