# Example 6 - Chapter 7 Class 10 Coordinate Geometry (Term 1)

Last updated at Aug. 16, 2021 by Teachoo

Examples

Example 1

Example 2 Important

Example 3 Important

Example 4

Example 5 Important

Example 6 You are here

Example 7 Important

Example 8

Example 9 Important

Example 10 Important

Example 11 Deleted for CBSE Board 2022 Exams

Example 12 Deleted for CBSE Board 2022 Exams

Example 13 Important Deleted for CBSE Board 2022 Exams

Example 14 Important Deleted for CBSE Board 2022 Exams

Example 15 Deleted for CBSE Board 2022 Exams

Last updated at Aug. 16, 2021 by Teachoo

Example 6 Find the coordinates of the point which divides the line segment joining the points (4, – 3) and (8, 5) in the ratio 3 : 1 internally. Let the given points be A(4, −3) & B(8, 5) Let the point be P(x, y) which divides AB in ratio 3 : 1 Finding x x = (𝑚1 𝑥2 + 𝑚2 𝑥1)/(𝑚1 + 𝑚2) Where, m1 = 3, m2 = 1 x1 = 4, x2 = 8 Putting values x = (3 × 8 + 1 ×4)/(3 + 1) x = (24 + 4)/4 x = 28/4 x = 7 Finding y y = (𝑚1 𝑦2 + 𝑚2 𝑦1)/(𝑚1 + 𝑚2) Where, m1 = 3, m2 = 1 y1 = −3, y2 = 5 Putting values y = (3 × 5 + 1 ×−3)/(3 +1 ) y = (15 − 3 )/4 y = (12 )/4 y = 3 Hence x = 7, y = 3 So, the required point is P(x, y) = P(7, 3)