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Example 6 - Chapter 7 Class 10 Coordinate Geometry (Term 1)
Last updated at Aug. 16, 2021 by Teachoo
Examples
Example 1
Example 2 Important
Example 3 Important
Example 4
Example 5 Important
Example 6 You are here
Example 7 Important
Example 8
Example 9 Important
Example 10 Important
Example 11 Deleted for CBSE Board 2023 Exams
Example 12 Deleted for CBSE Board 2023 Exams
Example 13 Important Deleted for CBSE Board 2023 Exams
Example 14 Important Deleted for CBSE Board 2023 Exams
Example 15 Deleted for CBSE Board 2023 Exams
Chapter 7 Class 10 Coordinate Geometry
Serial order wise
Transcript
Example 6 Find the coordinates of the point which divides the line segment joining the points (4, – 3) and (8, 5) in the ratio 3 : 1 internally. Let the given points be A(4, −3) & B(8, 5) Let the point be P(x, y) which divides AB in ratio 3 : 1 Finding x x = (𝑚1 𝑥2 + 𝑚2 𝑥1)/(𝑚1 + 𝑚2) Where, m1 = 3, m2 = 1 x1 = 4, x2 = 8 Putting values x = (3 × 8 + 1 ×4)/(3 + 1) x = (24 + 4)/4 x = 28/4 x = 7 Finding y y = (𝑚1 𝑦2 + 𝑚2 𝑦1)/(𝑚1 + 𝑚2) Where, m1 = 3, m2 = 1 y1 = −3, y2 = 5 Putting values y = (3 × 5 + 1 ×−3)/(3 +1 ) y = (15 − 3 )/4 y = (12 )/4 y = 3 Hence x = 7, y = 3 So, the required point is P(x, y) = P(7, 3)
