# Example 8 - Chapter 7 Class 10 Coordinate Geometry

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 8 Find the coordinates of the points of trisection (i.e., points dividing in three equal parts) of the line segment joining the points A(2, 2) and B( 7, 4). Let the given points be A(2, 2) & B( 7, 4) P & Q are two points on AB such that AP = PQ = QB Let k = AP = PQ = QB Hence comparing AP & PB AP = m PB = PQ + QB = k + k Hence, Ratio between AP & PB = AP/PB = /2 = 1/2 Thus P divides AB in the ratio 1:2 Finding P Let P(x, y) Hence, m1 = 1 , m2 = 2 And for AB x1 = 2 , x2 = 2 y1 = 7 , y2 = 4 Hence, point P is P(x, y) = P( 1, 0) Similarly, Point Q divides AB in the ratio AQ & QB = / = ( + )/ = ( + )/ = 2 / = 2/1 = 2 : 1 Finding Q Let Q be Q(x, y) m1 = 2 , m2 = 1 x1 = 2 , x2 = 2 y1 = 7 , y2 = 4 Hence, point Q is Q(x, y) = Q( 4, 2)

Chapter 7 Class 10 Coordinate Geometry

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.