Ex 7.1

Chapter 7 Class 10 Coordinate Geometry
Serial order wise

### Transcript

Ex 7.1, 6 Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer: (ii) (–3, 5), (3, 1), (0, 3), (–1, – 4) Let the points be A(−3, 5), B(3, 1) C(0, 3), D(−1, −4) We find the distances AB, BC, CD & AD By using distance formula Finding AB AB = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √(( 3 −(−3))2+(1 −5)2) = √((3+3)2+(−4)2) = √((6)2+(4)2) = √(36+16) = √52 Finding BC BC = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √((0 −3)2+(3 −1)2) = √((−3)2+(2)2) = √((3)2+(2)2) = √(9+4) = √13 Finding CD CD = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √((−1−0)2+(−4−3)2) = √((−1)2+(−7)2) = √((1)2+(7)2) = √(1+49) = √50 By using distance formula Finding AD AD = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √((−1−(−3))2+(−4−5)2) = √((−1+3)2+(−9)2) = √((2)2+(9)2) = √(4+81) = √85 Hence, AB = √52, BC = √13, CD = √50, AD = √85 Since, AB ≠ BC ≠ CD ≠ AD So, it is not a quadrilateral Why not a quadrilateral? Points are A(−3, 5), B(3, 1) C(0, 3) , D(−1, −4) Plotting them in a graph Here points A, B,C are collinear. So, ABCD is a triangle, not a quadrilateral

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#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.