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Ex 7.1, 2 Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2. Let the two points be P(0, 0) & Q(36, 15) We need to find distance PQ PQ = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) Here, x1 = x coordinate of P = 0 y1 = y coordinate of P = 0 x2 = x coordinate of Q = 36 y2 = y coordinate of Q = 15 Putting values PQ = √((36 −0 )2+(15 −0)2) PQ = √((36)2+(15)2) PQ = √((1296)+(225) ) PQ = √1521 PQ = 39 Now, we are told to find distance between two towns A & B in section 7.2 It is given that B is located 36 km east and 15 km north of town A Let us take A as origin. Therefore, A will be A(0, 0) & B will be B(36, 15) We have to find distance AB AB = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) Here, x1 = x coordinate of A = 0 y1 = y coordinate of A = 0 x2 = x coordinate of B = 36 y2 = y coordinate of B = 15 Putting values AB = √((36 −0 )2+(15 −0)2) = √((36)2+(15)2) = √((1296)+(225) ) = √1521 AB = 39 Therefore, the distance between the two towns is 39 km

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.