Ex 7.1, 2
Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2.
Let the two points be P(0, 0) & Q(36, 15)
We need to find distance PQ
PQ = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2)
Here, x1 = x coordinate of P = 0
y1 = y coordinate of P = 0
x2 = x coordinate of Q = 36
y2 = y coordinate of Q = 15
Putting values
PQ = √((36 −0 )2+(15 −0)2)
PQ = √((36)2+(15)2)
PQ = √((1296)+(225) )
PQ = √1521
PQ = 39
Now, we are told to find distance between two towns A & B in section 7.2
It is given that B is located
36 km east and 15 km north of town A
Let us take A as origin.
Therefore, A will be A(0, 0) &
B will be B(36, 15)
We have to find distance AB
AB = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2)
Here, x1 = x coordinate of A = 0
y1 = y coordinate of A = 0
x2 = x coordinate of B = 36
y2 = y coordinate of B = 15
Putting values
AB = √((36 −0 )2+(15 −0)2)
= √((36)2+(15)2)
= √((1296)+(225) )
= √1521
AB = 39
Therefore, the distance between the two towns is 39 km

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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