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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 7.1, 6 Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer: (iii) (4, 5), (7, 6), (4, 3), (1, 2) Let the points be A (4, 5), B (7, 6) C (4, 3), D (1, 2) We find the distances AB, BC, CD & AD By using distance formula Finding AB AB = √((𝑥2 −𝑥1)2+(𝑦2 −1)2) = √(( 7 −4)2+(6 −5)2) = √((3)2+(1)2) = √(9+1) = √10 Finding BC BC = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √(( 4 −7)2+(3 −6)2) = √((−3)2+(−3)2) = √((−3)2+(−3)2) = √((3)2+(3)2) = √(9+9) = √18 Finding CD CD = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √(( 1 −4)2+(2 −3)2) = √((−3)2+(−1)2) = √((3)2+(1)2) = √(9+1) = √10 Finding AD AD = √((𝑥2 −𝑥1)2+(𝑦2 −𝑦1)2) = √(( 1 −4)2+(2 −5)2) = √((−3)2+(−3)2) = √((3)2+(3)2) = √(9+9) = √18 Since, AB = CD = √10 & AD = BC = √18 Since both pairs of opposite sides of quadrilateral are equal, it would be a parallelogram

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.