Question 4 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at December 16, 2024 by

The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at

(A) (0, 0)                                (B) (0, 8)   

(C) (5, 0)                               (D) (4, 10)

 

This question is similar to Ex 12.2, 11 - Chapter 12 Class 12 - Linear Programming

Exemplar MCQ - The feasible solution for a LPP is shown in Fig. 12.12 - NCERT Exemplar - MCQs

part 2 - Question 4 (Case Based MCQ) - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming

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Question 4 The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at (A) (0, 0) (B) (0, 8) (C) (5, 0) (D) (4, 10) Checking value of Z = 3x – 4y at corner points Thus, Min Z = −32 at (0, 8) So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo