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Question 10 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming (Term 1)

Last updated at Nov. 19, 2021 by

Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).

Let F = 4x + 6y be the objective function.

 Maximum of F – Minimum of F =

(A)60                          (B) 48

(C) 42                         (D) 18

This question is similar to Question 38 Choice 2 - Sample Paper 2021 Class 12 - Linear Programming

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Question 10 Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let F = 4x + 6y be the objective function. Maximum of F – Minimum of F = 60 (B) 48 (C) 42 (D) 18 We need to find Max and Min F = 4x + 6y Corner Points are (0, 2), (3, 0), (6, 0), (6, 8), (0, 5) Checking value of F at corner points Thus, Max Z = 72 Min Z = 12 Therefore, Max value of Z − Min value of Z = 72 − 12 = 60 So, the correct answer is (D)

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