Question 10 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming (Term 1)
Last updated at Nov. 19, 2021 by Teachoo
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Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).
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Question 10
Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).
Let F = 4x + 6y be the objective function.
Maximum of F – Minimum of F =
60 (B) 48
(C) 42 (D) 18
We need to find Max and Min F = 4x + 6y
Corner Points are
(0, 2), (3, 0), (6, 0), (6, 8), (0, 5)
Checking value of F at corner points
Thus,
Max Z = 72
Min Z = 12
Therefore,
Max value of Z − Min value of Z = 72 − 12
= 60
So, the correct answer is (D)
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