Question 2 - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at August 12, 2026 by

Feasible region (shaded) for a LPP is shown in the Fig. 12.6. Minimum of Z = 4x + 3y occurs at the point

(A) (0, 8)                           (B) (2, 5)

(C) (4, 3)                           (D) (9, 0)

This question is similar to Ex 12.2, 1 - Chapter 12 Class 12 - Linear Programming

Linear Programming [MCQ] - Feasible region (shaded) for a LPP is shown - NCERT Exemplar - MCQs

part 2 - Question 2 - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming
part 3 - Question 2 - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming

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Transcript

Question 2 Feasible region (shaded) for a LPP is shown in the Fig. 12.6. Minimum of Z = 4x + 3y occurs at the point (A) (0, 8) (B) (2, 5) (C) (4, 3) (D) (9, 0) Corners points are (0, 8), (2, 5), (4, 3) and (9, 0) We need to Minimise Z = 4x + 3y Checking value of Z at all corner points Since the feasible region is unbounded, Hence, 23 may or may not be the minimum value of Z So, we need to graph inequality : Z < 23 4x + 3y < 23 As, there is no common points between the feasible region and the inequality. ∴ Min Z = 23 at (2, 5) So, the correct answer is (B)

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