Question 8 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at August 12, 2026 by

The feasible region for an LPP is shown in the Fig. 12.13. Let F = 3x – 4y be the objective function.. Minimum value of F is

(A)0                             (B) – 16

(C) 12                          (D) does not exist

 

This question is similar to Question 38 Choice 2 - Sample Paper 2021 Class 12 - Linear Programming

NCERT Exemplar Class 12 [MCQ] - The feasible region for an LPP is show - NCERT Exemplar - MCQs

part 2 - Question 8 (Case Based MCQ) - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming
part 3 - Question 8 (Case Based MCQ) - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming

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Transcript

Question 8 The feasible region for an LPP is shown in the Fig. 12.13. Let F = 3x – 4y be the objective function.. Minimum value of F is 0 (B) – 16 (C) 12 (D) does not exist Completing the feasible region Let the two lines intersect at (12, y) ∴ Corner Points of feasible region are (0, 0), (0, 4), (12, 6), (12, y) We need to find Min F = 3x – 4y Checking value of F at corner points Thus, We cannot find minimum of F) So, the correct answer is (D) – does not exist

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