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Question 11 Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is (A) p = 2q (B) p = ๐‘ž/2 (C) p = 3q (D) p = q Given corner points are (0, 3), (1, 1), (3, 0) Max. Z = px + qy Since maximum value of Z occurs on (3, 0) and (1, 1) Hence, Value on (3, 0) = Value on (1, 1) 3p = p + q 3p โˆ’ p = q 2p = q p = ๐’’/๐Ÿ โˆด Value of Z will be maximum if p = ๐’’/๐Ÿ So, the correct answer is (B)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.