Question 7 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at Dec. 16, 2024 by

The feasible region for an LPP is shown in the Fig. 12.13. Let F = 3x – 4y be the objective function. Maximum value of F is.

(A)0                           (B) 8

(C) 12                       (D) − 18

This question is similar to Question 38 Choice 2 - Sample Paper 2021 Class 12 - Linear Programming

[MCQ] Let F = 3x – 4y be the objective function. Maximum value of F is - NCERT Exemplar - MCQs

part 2 - Question 7 (Case Based MCQ) - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming
part 3 - Question 7 (Case Based MCQ) - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming

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Question 7 The feasible region for an LPP is shown in the Fig. 12.13. Let F = 3x – 4y be the objective function. Maximum value of F is. 0 (B) 8 (C) 12 (D) − 18 Completing the feasible region Let the two lines intersect at (12, y) ∴ Corner Points of feasible region are (0, 0), (0, 4), (12, 6), (12, y) We need to find Max F = 3x – 4y Checking value of F at corner points Thus, Max F = 12 at (12, 6) So, the correct answer is (C) y is greater than 6

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