1. Chapter 12 Class 12 Linear Programming (Term 1)
  2. Serial order wise
  3. NCERT Exemplar - MCQs

Question 5 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming (Term 1)

Last updated at Nov. 19, 2021 by

The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Maximum of Z occurs at

(A) (5, 0)             (B) (6, 5)  

(C) (6, 8)             (D) (4, 10)

 

This question is similar to Question 38 Choice 2 - Sample Paper 2021 Class 12 - Linear Programming

 

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  1. Chapter 12 Class 12 Linear Programming (Term 1)
  2. Serial order wise

    3. NCERT Exemplar - MCQs

    Linear equations given - Bounded →

Transcript

Question 5 The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. Maximum of Z occurs at (5, 0) (B) (6, 5) (C) (6, 8) (D) (4, 10) Checking value of Z = 3x – 4y at corner points Thus, Max Z = 15 at (5, 0) So, the correct answer is (A)

Chapter 12 Class 12 Linear Programming (Term 1)
Serial order wise

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