Question 1 - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming

Last updated at August 12, 2026 by

The corner points of the feasible region determined by the system of linear constraints are (0, 10), (5, 5), (15, 15), (0, 20).Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both the points (15, 15) and (0, 20) is

(A)p = q                   (B) p = 2q

(C) q = 2p               (D) q = 3p

This question is similar to Ex 12.2, 11 - Chapter 12 Class 12 - Linear Programming

Class 12 MCQ - The corner points of the feasible region determined - NCERT Exemplar - MCQs

part 2 - Question 1 - NCERT Exemplar - MCQs - Serial order wise - Chapter 12 Class 12 Linear Programming

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Transcript

Question 1 The corner points of the feasible region determined by the system of linear constraints are (0, 10), (5, 5), (15, 15), (0, 20).Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both the points (15, 15) and (0, 20) is p = q (B) p = 2q (C) q = 2p (D) q = 3p Given corner points are (0, 10), (5, 5), (15, 15), (0, 20) Max. Z = px + qy Since maximum value of Z occurs on (15, 15) and (0, 20) Hence, Value on (15, 15) = Value on (0, 20) 15p + 15q = 20q 15p = 20q − 15q 15p = 5q 15𝑝/5 = q 3p = q q = 3p ∴ Value of Z will be maximum if q = 3p So, the correct answer is (D)

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