Ex 12.2, 11 - The corner points of feasible region determined - Linear equations given - Bounded

Slide58.PNG

  1. Chapter 12 Class 12 Linear Programming
  2. Serial order wise
Ask Download

Transcript

Ex 12.2, 11 The corner points of the feasible region determined by the following system of linear inequalities: 2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is (A) p = q (B) p = 2q (C) p = 3q (B) q = 3p Constraints 2x + y ≤ 10 x + 3y ≤ 0 x, y ≥ 0 Max. Z = px + qy Since maximum value of Z occurs on (3, 4) and (0, 5) Hence value on (3, 4) = value on (0, 5) 3p + 4q = 5q 3p = 5q − 4q 3p = q ∴ Value of Z will be maximum if q = 3p ∴ (D) is correct answer

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.
Jail