# Ex 12.2, 11 - Chapter 12 Class 12 Linear Programming

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 12.2, 11 The corner points of the feasible region determined by the following system of linear inequalities: 2x + y 10, x + 3y 15, x, y 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is (A) p = q (B) p = 2q (C) p = 3q (B) q = 3p Constraints 2x + y 10 x + 3y 0 x, y 0 Max. Z = px + qy Since maximum value of Z occurs on (3, 4) and (0, 5) Hence value on (3, 4) = value on (0, 5) 3p + 4q = 5q 3p = 5q 4q 3p = q Value of Z will be maximum if q = 3p (D) is correct answer

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