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Ex 12.2
Ex 12.2, 2 Deleted for CBSE Board 2023 Exams
Ex 12.2, 3 Important Deleted for CBSE Board 2023 Exams
Ex 12.2, 4 Important Deleted for CBSE Board 2023 Exams
Ex 12.2, 5 Deleted for CBSE Board 2023 Exams
Ex 12.2, 6 Deleted for CBSE Board 2023 Exams
Ex 12.2, 7 Important Deleted for CBSE Board 2023 Exams
Ex 12.2, 8 Deleted for CBSE Board 2023 Exams
Ex 12.2, 9 Important Deleted for CBSE Board 2023 Exams
Ex 12.2, 10 Important Deleted for CBSE Board 2023 Exams
Ex 12.2, 11 (MCQ) Important Deleted for CBSE Board 2023 Exams You are here
Last updated at March 30, 2023 by Teachoo
Ex 12.2, 11 The corner points of the feasible region determined by the following system of linear inequalities: 2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is (A) p = q (B) p = 2q (C) p = 3q (B) q = 3p Constraints 2x + y ≤ 10 x + 3y ≤ 15 x, y ≥ 0 Max. Z = px + qy Since maximum value of Z occurs on (3, 4) and (0, 5) Hence, Value on (3, 4) = Value on (0, 5) 3p + 4q = 5q 3p = 5q − 4q 3p = q ∴ Value of Z will be maximum if q = 3p ∴ (D) is correct answer