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Forming equations and solving
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Question 11 (MCQ) Important Deleted for CBSE Board 2024 Exams You are here
Forming equations and solving
Last updated at May 29, 2023 by Teachoo
Question 11 The corner points of the feasible region determined by the following system of linear inequalities: 2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is (A) p = q (B) p = 2q (C) p = 3q (B) q = 3p Constraints 2x + y ≤ 10 x + 3y ≤ 15 x, y ≥ 0 Max. Z = px + qy Since maximum value of Z occurs on (3, 4) and (0, 5) Hence, Value on (3, 4) = Value on (0, 5) 3p + 4q = 5q 3p = 5q − 4q 3p = q ∴ Value of Z will be maximum if q = 3p ∴ (D) is correct answer