# Ex 12.2, 5 - Chapter 12 Class 12 Linear Programming (Term 1)

Last updated at May 29, 2018 by Teachoo

Ex 12.2

Ex 12.2, 1
Important
Deleted for CBSE Board 2023 Exams

Ex 12.2, 2 Deleted for CBSE Board 2023 Exams

Ex 12.2, 3 Important Deleted for CBSE Board 2023 Exams

Ex 12.2, 4 Important Deleted for CBSE Board 2023 Exams

Ex 12.2, 5 Deleted for CBSE Board 2023 Exams You are here

Ex 12.2, 6 Deleted for CBSE Board 2023 Exams

Ex 12.2, 7 Important Deleted for CBSE Board 2023 Exams

Ex 12.2, 8 Deleted for CBSE Board 2023 Exams

Ex 12.2, 9 Important Deleted for CBSE Board 2023 Exams

Ex 12.2, 10 Important Deleted for CBSE Board 2023 Exams

Ex 12.2, 11 (MCQ) Important Deleted for CBSE Board 2023 Exams

Chapter 12 Class 12 Linear Programming

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 12.2, 5 A factory manufactures two types of screws, A and B. Each type of screw requires the use of two machines, an automatic and a hand operated. It takes 4 minutes on the automatic and 6 minutes on hand operated machines to manufacture a package of screws A, while it takes 6 minutes on automatic an 3 minutes on the hand operated machines to manufacture a package of screws B. Each machine is available for at the most 4 hours on any day. The manufacturer can sell a package of screws A at a profit of Rs 7 and screws B at a profit of Rs 10. Assuming that he can sell all the screws he manufactures, how many packages of each type should the factory owner produce in a day in order to maximise his profit? Determine the maximum profit. Let the number of packages of Screw A be x number of packages of screw B be y. According to Question : As, we need to Maximize the Profit, the Function used here is Maximize Z. Profit on Screw A Rs 7 Profit on Screw B Rs 10 Maximize Z = 7x + 10y Combining all Constraints Max Z = 7x + 10y Subject to constraints : 2x + 3y 120 2x + y 80 x 0, y 0. Hence, Profit will be maximum if the Company produces : 30 packages of Screw A 20 packages of Screw B Maximum Profit = Rs 410