Question 6 (Case Based MCQ) - NCERT Exemplar - MCQs - Chapter 12 Class 12 Linear Programming (Term 1)
Last updated at Nov. 20, 2021 by Teachoo
The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. (Maximum value of Z + Minimum value of Z) is equal to
Question 6
The feasible solution for a LPP is shown in Fig. 12.12. Let Z = 3x – 4y be the objective function. (Maximum value of Z + Minimum value of Z) is equal to
13 (B) 1 (C) −13 (D) − 17
Checking value of Z = 3x – 4y at corner points
Thus,
Max Z = 15 at (5, 0)
Min Z = −32 at (0, 8)
Therefore,
Maximum value of Z + Minimum value of Z = 15 + (−32)
= 15 − 32
= −17
So, the correct answer is (D)
Made by
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.