If 4 tan β = 3, then (4 sin⁡β  - 3 cos⁡β)/(4 sin⁡β  + 3 cos⁡β ) =

(a) 0  (b) 1/3      (c) 2/3        (d) 3/4 

 

This question is inspired from Question 15 - NCERT Exemplar - MCQ - Chapter 8 Class 10 - Introduction to Trignometry

 

Ques 18 (MCQ) - If 4 tan β = 3, then (4 sin β - 3 cos β) / (4 sin β + - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ]

part 2 - Question 18 - CBSE Class 10 Sample Paper for 2022 Boards - Maths Standard [MCQ] - Solutions of Sample Papers for Class 10 Boards - Class 10

Remove Ads

Transcript

Question 18 If 4 tan β = 3, then (4 sin⁡𝛽 − 3 cos⁡𝛽)/(4 sin⁡𝛽 + 3 cos⁡𝛽 ) = (a) 0 (b) 1/3 (c) 2/3 (d) 3/4 Given 4 tan β = 3 tan β = 𝟑/𝟒 Now, (4 sin⁡〖𝛽 − 3 cos⁡𝛽 〗)/(4 sin⁡〖𝛽 + 〖3 cos〗⁡𝛽 〗 ) Dividing numerator and denominator by cos θ = (4 sin⁡𝛽/cos⁡𝛽 − 3 cos⁡𝛽/cos⁡𝛽 )/(4 sin⁡𝛽/cos⁡𝛽 + 3 cos⁡𝛽/cos⁡𝛽 ) = (𝟒 𝐭𝐚𝐧⁡〖𝛽 − 𝟑〗)/(𝟒 𝐭𝐚𝐧⁡〖𝜽 + 𝟑〗 ) Putting tan 𝛽 = 𝟑/𝟒 = (4 × 3/4 − 3)/(4 × 3/4 + 3) = (3 − 3)/(3 + 3) = 0/6 = 0 So, the correct answer is (a)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo