If A = [8(0 2 3 -4)] and kA = [8(0 3a 2b 24)], then the values of 𝑘,𝑎 and 𝑏 respectively are:

(a) −6, −12, −18          (b) −6, −4, −9

(c) −6, 4, 9                   (d) −6, 12, 18

Ques 32 (MCQ) - SQP Class 12 - If A = [ 0 2 3 −4 ] and 𝑘A = [ 0 3𝑎 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)

part 2 - Question 32 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12
part 3 - Question 32 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

Share on WhatsApp

Transcript

Question 32 If A = [■8(0&2@3&−4)] and kA = [■8(0&3𝑎@2𝑏&24)], then the values of 𝑘,𝑎 and 𝑏 respectively are: (a) −6, −12, −18 (b) −6, −4, −9 (c) −6, 4, 9 (d) −6, 12, 18 Now, A = [■8(0&2@3&−4)] kA = k [■8(0&2@3&−4)] kA = [■8(0 × 𝑘&2 × 𝑘@3 × 𝑘&−4 × 𝑘)] kA = [■8(0&2𝑘@3𝑘&−4𝑘)] Putting value of kA [■8(0&3𝑎@2𝑏&24)] = [■8(0&2𝑘@3𝑘&−4𝑘)] Thus, 24 = −4k −4k = 24 k = 24/(−4) k = −6 Also, 3a = 2k 3a = 2(−6) 3a = −12 a = (−12)/3 a = −4 So, the correct answer is (B) [■8(0&3𝑎@2𝑏&24)] = [■8(0&2𝑘@3𝑘&−4𝑘)] Thus, 24 = −4k −4k = 24 k = 24/(−4) k = −6 Also, 3a = 2k 3a = 2(−6) 3a = −12 a = (−12)/3 a = −4 2b = 3k 2b = 3(−6) 2b = −18 b = (−18)/2 b = −9 Thus, k = −6, a = −4, b = −9 So, the correct answer is (B)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo