If A = [aij] is a square matrix of order 2 such that aij = {(1,Ā  when i ≠j 0,Ā  when i=jĀ  )┤ , then A2 is :

(a) [8(1 0 1 0)]Ā  (b) [8(1 1 0 0)]Ā  Ā  Ā  (c) [8(1 1 1 0)]Ā  (d) [8(1 0 0 1)]Ā 

Ques 3 (MCQ) - If A = [aij] is a square matrix of order 2 such that - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1)

part 2 - Question 3 - CBSE Class 12 Sample Paper for 2022 Boards (MCQ Based - for Term 1) - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 3 If A = [š‘Žš‘–š‘—] is a square matrix of order 2 such that š‘Žš‘–š‘— = {ā–ˆ(1, š‘¤ā„Žš‘’š‘› š‘– ā‰ š‘—@0, š‘¤ā„Žš‘’š‘› š‘–=š‘— )┤ , then A2 is : (a) [ā– 8(1&0@1&0)] (b) [ā– 8(1&1@0&0)] (c) [ā– 8(1&1@1&0)] (d) [ā– 8(1&0@0&1)] For a 2 Ɨ 2 matrix A = [ā– 8(š‘Ž_11&š‘Ž_12@š‘Ž_21&š‘Ž_22 )] Given that š‘Ž_š‘–š‘—={ā–ˆ(1, š‘–ā‰  š‘—@0, š‘–=š‘—)┤ Thus, š‘Ž_11 = 0, š‘Ž_22 = 0 , š‘Ž_12 = 1, š‘Ž_21 = 1 So, our matrix becomes A = [ā– 8(šŸŽ&šŸ@šŸ&šŸŽ)] Now, A2 = [ā– 8(0&1@1&0)][ā– 8(0&1@1&0)] = [ā– 8(0(0)+1(1)&0(1)+1(0)@1(0)+0(1)&1(1)+0(0))] = [ā– 8(šŸ&šŸŽ@šŸŽ&šŸ)] So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo