Cross Multiplication Method
Question 1 (ii) Important Deleted for CBSE Board 2025 Exams
Question 1 (iii) Deleted for CBSE Board 2025 Exams You are here
Question 1 (iv) Important Deleted for CBSE Board 2025 Exams
Question 2 (i) Important Deleted for CBSE Board 2025 Exams
Question 2 (ii) Deleted for CBSE Board 2025 Exams
Question 3 Deleted for CBSE Board 2025 Exams
Question 4 (i) Deleted for CBSE Board 2025 Exams
Question 4 (ii) Deleted for CBSE Board 2025 Exams
Question 4 (iii) Deleted for CBSE Board 2025 Exams
Question 4 (iv) Important Deleted for CBSE Board 2025 Exams
Question 4 (v) Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Ex 3.5 ,1 Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions. In case there is a unique solution, find it by using cross multiplication method (iii) 3x – 5y = 20 6x – 10y = 40 3x – 5y = 20 6x – 10y = 40 3x – 5y = 20 3x – 5y – 20 = 0 Comparing with a1x + b1y + c1 = 0 ∴ a1 = 3,b1 = –5,c1 = –20 6x – 10y = 40 6x – 10y – 40 = 0 Comparing with a2x + b2y + c2 = 0 ∴ a2 = 6,b2 = –10,c2 = –40 a1 = 3, b1 = –5, c1 = –20 & a2 = 6, b2 = –10, c2 = –40 𝒂𝟏/𝒂𝟐 𝑎1/𝑎2 = 3/6 𝑎1/𝑎2 = 1/2 𝒃𝟏/𝒃𝟐 𝑏1/𝑏2 = (−5)/(−10) 𝑏1/𝑏2 = 1/2 𝒄𝟏/𝒄𝟐 𝑐1/𝑐2 = (−20)/(−40) 𝑐1/𝑐2 = 1/2 Since 𝒂𝟏/𝒂𝟐 = 𝒃𝟏/𝒃𝟐 = 𝒄𝟏/𝒄𝟐 We have infinitely many solutions