Last updated at July 24, 2021 by Teachoo

Transcript

Ex 3.5, 4 Form the pair of linear equations in the following problems and find their solutions (if they exist) by any algebraic method : (ii) A fraction becomes 1/3 when 1 is subtracted from the numerator & it becomes 1/4 when 8 is added to its denominator. Find the fraction Let Numerator be x & Denominator be y So, Fraction is ๐/๐ Given that, If 1 is subtracted from numerator fraction becomes 1/3. (๐๐ข๐๐๐๐๐ก๐๐ โ 1)/(๐ท๐๐๐๐๐๐๐๐ก๐๐ )=1/3 (๐ฅ โ 1)/(๐ฆ )=1/3 3(x โ 1) = y 3x โ 3 = y 3x โ y = 3 Also, If 8 is added to the denominator, fraction becomes 1/4. (๐๐ข๐๐๐๐๐ก๐๐ )/(๐ท๐๐๐๐๐๐๐๐ก๐๐ + 8)=1/4 (๐ฅ )/(๐ฆ + 8)=1/4 4x = y + 8 4x โ y = 8 From (1) 3x โ y = 3 3x = y + 3 x = ((๐ + ๐)/๐) Putting value of x in (2) 4x โ y โ 8 = 0 4 ((๐ฆ + 3)/3) โ y โ 8 = 0 Multiplying both sides by 3 3 ร "4" ((๐ฆ + 3)/3)โ"3 ร " ๐ฆโ"3 ร 8"="3 ร" 0 4(y + 3 ) โ 3y โ 24 = 0 4y + 12 โ 3y โ 24 = 0 y โ 12 = 0 y = 12 Putting y = 12 in equation (1) 3x โ y = 3 3x โ 12 = 3 3x = 12 + 3 3x = 15 x = 15/3 x = 5 Therefore x = 5, y = 12 is the solution So, Numerator = x = 5 Denominator = y = 12 โด Original fraction = ๐๐ข๐๐๐๐๐ก๐๐/๐ท๐๐๐๐๐๐๐๐ก๐๐ "= " ๐/๐=๐/๐๐

Ex 3.5

Ex 3.5, 1 (i)
Deleted for CBSE Board 2022 Exams

Ex 3.5, 1 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 3.5, 1 (iii) Deleted for CBSE Board 2022 Exams

Ex 3.5, 1 (iv) Important Deleted for CBSE Board 2022 Exams

Ex 3.5, 2 (i) Important

Ex 3.5, 2 (ii)

Ex 3.5, 3 Deleted for CBSE Board 2022 Exams

Ex 3.5, 4 (i)

Ex 3.5, 4 (ii) You are here

Ex 3.5, 4 (iii)

Ex 3.5, 4 (iv) Important

Ex 3.5, 4 (v) Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.