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Ex 3.2, 1 (ii) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables
Last updated at August 17, 2026 by Teachoo
Chapter 3 Class 10 Pair of Linear Equations in Two Variables
Serial order wise
- Ex 3.1
-
Ex 3.2
- Ex 3.3
- Examples
- Case Based Questions (MCQ)
- MCQs from NCERT Exemplar
- Graph of pair of Linear Equations
- Cross Multiplication Method
- Equations reduced to pair of linear equations
- Important Linear Equation Questions
- Teachoo Questions - MCQs
- Teachoo Questions - Mix
- Teachoo Questions - Assertion Reasoning
- Teachoo Questions - Case Based
Transcript
Ex 3.2, 1 Solve the following pair of linear equations by the substitution method. (ii) s – t = 3 𝑠/3+𝑡/2=6 s – t = 3 𝑠/3+𝑡/2=6 From (1) s – t = 3 s = 3 + t Substituting s = 3 + t in (2) (3 + 𝑡)/3+𝑡/2=6 ((3 + 𝑡) × 2 + 𝑡 × 3)/(3 × 2)=6 (6 + 2𝑡 + 3𝑡)/6=6 (6 + 5𝑡)/6=6 6 + 5t = 6 × 6 6 + 5t = 36 5t = 36 – 6 5t = 30 t = 30/5 t = 6 Putting t = 6 in (1) s – t = 3 s = 3 + 6 s = 9 Hence, s = 9, t = 6
