Ex 3.2, 1 (v) - Solve the pair of linear equations by substitution - Ex 3.2

part 2 - Ex 3.2, 1 (v) - Ex 3.2 - Serial order wise - Chapter 3 Class 10 Pair of Linear Equations in Two Variables
part 3 - Ex 3.2, 1 (v) - Ex 3.2 - Serial order wise - Chapter 3 Class 10 Pair of Linear Equations in Two Variables

 

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Transcript

Substituting x in (2) √3 𝑥−√8 𝑦=0 √3 ((−√3 𝑦)/√2)−√8 𝑦 = 0 (√3 × (−√3 𝑦))/√2−√8 𝑦=0 (−3𝑦)/√2−√8 𝑦=0 –3y – √8 𝑦 × √2= √2 × 0 –3y – √(8 × 2) 𝑦=0 –3y – √16 𝑦=0 –3y – √(4 × 4) 𝑦=0 –3y – √42 𝑦=0 –3y – 4y = 0 –7y = 0 y = 0/(−7) y = 0 Putting the value of y in (1) √2 𝑥+√3 𝑦=0 √2 𝑥+√3 × 0=0 √2 𝑥+0=0 √2 𝑥=0 x = 0/√2 x = 0 Hence, x = 0, y = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo