Last updated at May 29, 2018 by Teachoo

Transcript

Ex 3.3 , 2 Solve 2x + 3y = 11 and 2x 4y = 24 and hence find the value of m for which y = mx + 3. 2x + 3y = 11 2x 4y = 24 From (1) 2x + 3y = 11 2x = 11 3y x = (11 3 )/2 Substituting x in (2) 2x 4y = 24 2 ((11 3 )/2) 4 = 24 11 3y 4y = 24 11 7y = 24 7y = 24 11 7y = 35 y = ( 35)/( 7) y = 5 Putting y = 5 in (1) 2x + 3y = 11 2x + 3(5) = 11 2x + 15 = 11 2x = 11 15 2x = 4 x = ( 4)/2 x = 2 Hence x = - 2 and y = 5 is the solution of the equation Now, We have to find the value of m y = mx + 3 Putting y = 5, x = - 2 5 = m( 2) + 3 5 = 2m + 3 5 3 = 2m 2 = 2m m = 2/( 2) m = 1 Thus, value of m is 1

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.