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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 3.2, 2 Solve 2x + 3y = 11 and 2x – 4y = – 24 and hence find the value of ‘m’ for which y = mx + 3. 2x + 3y = 11 2x – 4y = –24 From (1) 2x + 3y = 11 2x = 11 – 3y x = (𝟏𝟏 − 𝟑𝒚)/𝟐 Substituting value of x in (2) 2x – 4y = – 24 2 ((11 − 3𝑦)/2)−4𝑦 = – 24 11 – 3y – 4y = – 24 11 – 7y = – 24 –7y = – 24 – 11 –7y = – 35 y = (−35)/(−7) y = 5 Putting y = 5 in (1) 2x + 3y = 11 2x + 3(5) = 11 2x + 15 = 11 2x = 11 – 15 2x = – 4 x = (−4)/2 x = –2 Hence, x = −2 and y = 5 is the solution of the equation Now, We have to find the value of m y = mx + 3 Putting y = 5, x = −2 5 = m(–2) + 3 5 = – 2m + 3 5 – 3 = –2m 2 = –2m m = 2/(−2) m = –1 Thus, value of m is –1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.