Ex 3.3

Chapter 3 Class 10 Pair of Linear Equations in Two Variables
Serial order wise

Β

Get live Maths 1-on-1 Classs - Class 6 to 12

### Transcript

Ex 3.3, 1 Solve the following pair of linear equations by the substitution method. (vi) 3π₯/2β5π¦/3=β2 π₯/3+π¦/2=13/6 Removing fractions from both equations ππ/πβππ/π=β2 Multiplying both equations by 6 6 Γ 3π₯/2β"6 Γ" 5π¦/3="6 Γ"β2 9x β 10y = β 12 π/π+π/π=ππ/π Multiplying both equations by 6 6 Γ π₯/3+"6 Γ" π¦/2="6 Γ " 13/6 2x + 3y = 13 Hence, our equations are 9x β 10y = β12 β¦(1) 2x + 3y = 13 β¦(2) From (1) 9x β 10y = β12 9x = β12 + 10y x = ((βππ + πππ)/π) Substituting value of x in (2) 2x + 3y = 13 2((β12 + 10π¦)/9)+3π¦=13 Multiplying both sides by 9 9 Γ 2((β12 + 10π¦)/9) + 9 Γ 3y = 9 Γ 13 (2(β12 + 10π¦) + 9 Γ 3π¦)/9=13 2(β12 + 10y) + 27y = 13Γ9 β 24 + 20y + 27y = 117 β 24 + 20y + 27y β 117 = 0 47y β 141 = 0 47y = 141 y = 141/47 y = 3 Putting y = 3 in (2) 2x + 3y = 13 2x + 3(3) = 13 2x + 9 = 13 2x = 13 β 9 2x = 4 x = 4/2 x = 2 Hence, x = 2, y = 3 is the solution of equation .