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Ex 10.5, 12 - Prove that cyclic parallelogram is a rectangle - Ex 10.5

  1. Chapter 10 Class 9 Circles
  2. Serial order wise
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Ex 10.5, 12 Prove that a cyclic parallelogram is a rectangle. Given: Let ABCD be a cyclic parallelogram To prove: ABCD is a rectangle Proof: A rectangle is a parallelogram with one angle 90° So, we have to prove angle 90° Since ABCD is a parallelogram ∠A = ∠C In cyclic parallelogram ABCD ∠A + ∠C = 180° ∠A + ∠A = 180° 2∠A = 180° ∠A = (180°)/2 = 90° So, ABCD is a parallelogram with one angle 90° Hence, ABCD is a rectangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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