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Ex 10.5, 12 - Prove that cyclic parallelogram is a rectangle - Ex 10.5

Ex 10.5, 12 - Chapter 10 Class 9 Circles - Part 2


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Ex 10.5, 12 Prove that a cyclic parallelogram is a rectangle. Given: Let ABCD be a cyclic parallelogram To prove: ABCD is a rectangle Proof: A rectangle is a parallelogram with one angle 90 So, we have to prove angle 90 Since ABCD is a parallelogram A = C In cyclic parallelogram ABCD A + C = 180 A + A = 180 2 A = 180 A = (180 )/2 = 90 So, ABCD is a parallelogram with one angle 90 Hence, ABCD is a rectangle

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.