Ex 10.5, 4 - In figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC - Ex 10.5

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Ex 9.3, 4 In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC. In ΔABC, ∠BAC + ∠ABC + ∠ACB = 180° ∠BAC + 69° + 31° = 180° ∠BAC + 100° = 180° ∠BAC = 180° − 100° ∠BAC = 80° For segment BADCB, ∠ BDC & ∠ BAC are angles in the same segment So, they must be equal ∴ ∠ BDC = ∠ BAC ⇒ ∠BDC = 80°

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.