1. Chapter 10 Class 9 Circles (Term 2)
  2. Serial order wise
  3. Ex 10.5

Ex 10.5, 4 - Chapter 10 Class 9 Circles (Term 2)

Last updated at Aug. 25, 2021 by

Ex 10.5, 4 - In figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC - Ex 10.5

  1. Chapter 10 Class 9 Circles (Term 2)
  2. Serial order wise

    3. Ex 10.5

    Examples →

Transcript

Ex 10.5, 4 In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC. In ΔABC, ∠BAC + ∠ABC + ∠ACB = 180° ∠BAC + 69° + 31° = 180° ∠BAC + 100° = 180° ∠BAC = 180° − 100° ∠BAC = 80° For segment BADCB, ∠ BDC & ∠ BAC are angles in the same segment So, they must be equal ∴ ∠ BDC = ∠ BAC ⇒ ∠BDC = 80°

Chapter 10 Class 9 Circles (Term 2)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.