Check sibling questions

Ex 10.5, 3 - In figure, ∠PQR = 100°, where P, Q and R - Cyclic quadrilaterals

Ex 10.5, 3 - Chapter 10 Class 9 Circles - Part 2

This video is only available for Teachoo black users

Solve all your doubts with Teachoo Black (new monthly pack available now!)


Transcript

Ex 10.5, 3 In the given figure, PQR = 100 , where P, Q and R are points on a circle with centre O. Find OPR. Here, PR is chord We mark point S on the major arc of the circle. PQRS is a cyclic quadrilateral. So, PQR + PSR = 180 100 + PSR = 180 PSR = 180 100 PSR = 80 Arc PQR subtends POR at centre of circle. And PSR on point S So, POR = 2 PSR POR = 2 (80 ) = 160 Now, In OPR OP = OR OPR = ORP Also, in OPR OPR + ORP + POR = 180 OPR + OPR + POR = 180 2 OPR + 160 = 180 2 OPR = 180 160 2 OPR = 20 OPR = (20 )/2 OPR = 10

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.