Check sibling questions

Ex 9.3, 3 - Chapter 9 Class 9 Circles

Last updated at May 29, 2023 by

Ex 10.5, 3 - In figure, ∠PQR = 100°, where P, Q and R - Cyclic quadrilaterals

Ex 10.5, 3 - Chapter 10 Class 9 Circles - Part 2

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Book a free demo

Transcript

Ex 9.3, 3 In the given figure, PQR = 100 , where P, Q and R are points on a circle with centre O. Find OPR. Here, PR is chord We mark point S on the major arc of the circle. PQRS is a cyclic quadrilateral. So, PQR + PSR = 180 100 + PSR = 180 PSR = 180 100 PSR = 80 Arc PQR subtends POR at centre of circle. And PSR on point S So, POR = 2 PSR POR = 2 (80 ) = 160 Now, In OPR OP = OR OPR = ORP Also, in OPR OPR + ORP + POR = 180 OPR + OPR + POR = 180 2 OPR + 160 = 180 2 OPR = 180 160 2 OPR = 20 OPR = (20 )/2 OPR = 10

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.