Example 9 - D is a point on side BC of ABC such that AD = AC - Side inequality

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Example 9 D is a point on side BC of Δ ABC such that AD = AC (see figure). Show that AB > AD. AD = AC So, ∠ ACD = ∠ ADC Now, ∠ ADC is an exterior angle for ΔABD. ∠ ADC = ∠ ABD + ∠ BAD So, ∠ ADC > ∠ ABD ∠ ACD > ∠ ABD AB > AC ∴ AB > AD Hence proved

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