Example 8
P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them.
Given:
PB = PC
& PBA = PCA = 90
To prove: PAB = PAC
Proof
In PAB and PAC.
PBA = PCA
PA = PA
PB = PC
So, PAB PAC
PAB = PAC
Hence proved.
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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