Example 8 - P is a point equidistant from two lines l and m - Examples

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Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & PBA = PCA = 90 To prove: PAB = PAC Proof In PAB and PAC. PBA = PCA PA = PA PB = PC So, PAB PAC PAB = PAC Hence proved.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.