Example 8 - P is a point equidistant from two lines l and m - Examples

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
Ask Download

Transcript

Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & ∠ PBA = ∠ PCA = 90° To prove: ∠ PAB = ∠ PAC Proof In Δ PAB and Δ PAC. ∠ PBA = ∠ PCA PA = PA PB = PC So, Δ PAB ≅ Δ PAC ∴ ∠ PAB = ∠ PAC Hence proved.

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
Jail