Example 8 - Chapter 7 Class 9 Triangles

Last updated at August 14, 2026 by

Example 8 - P is a point equidistant from two lines l and m - Examples

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Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & PBA = PCA = 90 To prove: PAB = PAC Proof In PAB and PAC. PBA = PCA PA = PA PB = PC So, PAB PAC PAB = PAC Hence proved.

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