1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise
  3. Examples

Example 8 - Chapter 7 Class 9 Triangles (Term 1)

Last updated at May 29, 2018 by

Example 8 - P is a point equidistant from two lines l and m - Examples

  1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise

    3. Examples

    Theorems →

Transcript

Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & PBA = PCA = 90 To prove: PAB = PAC Proof In PAB and PAC. PBA = PCA PA = PA PB = PC So, PAB PAC PAB = PAC Hence proved.

Chapter 7 Class 9 Triangles (Term 1)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.