Last updated at March 16, 2017 by Teachoo
Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & ∠ PBA = ∠ PCA = 90° To prove: ∠ PAB = ∠ PAC Proof In Δ PAB and Δ PAC. ∠ PBA = ∠ PCA PA = PA PB = PC So, Δ PAB ≅ Δ PAC ∴ ∠ PAB = ∠ PAC Hence proved.
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