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Chapter 7 Class 9 Triangles
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Ex 7.5, 1 (Optional) - ABC is a triangle. Locate a point in interior

Ex 7.5, 1 (Optional) - Chapter 7 Class 9 Triangles - Part 2
Ex 7.5, 1 (Optional) - Chapter 7 Class 9 Triangles - Part 3 Ex 7.5, 1 (Optional) - Chapter 7 Class 9 Triangles - Part 4


Transcript

Ex 7.5, 1 (Optional) ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of Δ ABC. An interior point which is equidistant from all the vertices of ∆ABC is its circumcentre Let’s draw a circle passing through points A, B, C So, Center of a circle will be equidistant from points A, B, C Center of circle will be the intersection of perpendicular bisector of sides of the triangle. Because perpendicular bisector of a chord passes through the center. Finding Center of circle Draw perpendicular bisector of AB Take a compass. With point A as pointy end and B as pencil end of the compass, mark an arc above and below AB. Do same with B as pointy end and A as pencil end of the compass. Draw perpendicular bisector of AC Take a compass. With point A as pointy end and C as pencil end of the compass, mark an arc above and below AC. Do same with C as pointy end and A as pencil end of the compass. 3. Mark point O where two perpendicular bisectors intersect. Hence, O is the center of the circle Thus, point O is the point in the interior of Δ ABC equidistant from points A, B and C

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.