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Example 5 - E & F are mid-points of equal sides AB and AC - SAS

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Example 5 E and F are respectively the mid-points of equal sides AB and AC of ∆ ABC (see figure). Show that BF = CE. Given: AB = AC E is the mid-point of AB & F is the mid-point of AC To prove: BF = CE Proof: Given AB = AC 1/2 AB = 1/2 AC AE = AF In ∆ ABF and ∆ ACE, AB = AC ∠ A = ∠ A AF = AE So, ∆ ABF ≅ ∆ ACE ∴ BF = CE Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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