Example 5 - E & F are mid-points of equal sides AB and AC - SAS

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise


Example 5 E and F are respectively the mid-points of equal sides AB and AC of ABC (see figure). Show that BF = CE. Given: AB = AC E is the mid-point of AB & F is the mid-point of AC To prove: BF = CE Proof: Given AB = AC 1/2 AB = 1/2 AC AE = AF In ABF and ACE, AB = AC A = A AF = AE So, ABF ACE BF = CE Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.