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Example 2 - Chapter 7 Class 9 Triangles (Term 1)

Last updated at May 29, 2018 by

Example 2 - AB is a line segment and line l is perpendicular - Examples

Example 2 - Chapter 7 Class 9 Triangles - Part 2

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Example 2 AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B Given: Line l is perpendicular to AB So, PCA = PCB = 90 & Line l bisects line AB (as it is perpendicular bisector) AC = BC To prove: PA = PB Proof: Consider PCA and PCB. AC = BC PCA = PCB PC = PC PCA PCB So, PA = PB Hence proved

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