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Example 2 - AB is a line segment and line l is perpendicular - Examples

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Example 2 AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B Given: Line l is perpendicular to AB So, ∠ PCA = ∠ PCB = 90° & Line l bisects line AB (as it is perpendicular bisector) AC = BC To prove: PA = PB Proof: Consider Δ PCA and Δ PCB. AC = BC ∠ PCA = ∠ PCB PC = PC Δ PCA ≅ Δ PCB So, PA = PB Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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