Example 2 AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B Given: Line l is perpendicular to AB So, PCA = PCB = 90 & Line l bisects line AB (as it is perpendicular bisector) AC = BC To prove: PA = PB Proof: Consider PCA and PCB. AC = BC PCA = PCB PC = PC PCA PCB So, PA = PB Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.