Last updated at May 29, 2018 by Teachoo

Transcript

Example 2 AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B Given: Line l is perpendicular to AB So, PCA = PCB = 90 & Line l bisects line AB (as it is perpendicular bisector) AC = BC To prove: PA = PB Proof: Consider PCA and PCB. AC = BC PCA = PCB PC = PC PCA PCB So, PA = PB Hence proved

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.