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Example 8 - P is a point equidistant from two lines l and m - Examples

  1. Class 9
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Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & ∠ PBA = ∠ PCA = 90° To prove: ∠ PAB = ∠ PAC Proof In Δ PAB and Δ PAC. ∠ PBA = ∠ PCA PA = PA PB = PC So, Δ PAB ≅ Δ PAC ∴ ∠ PAB = ∠ PAC Hence proved.

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CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
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