Last updated at May 29, 2018 by Teachoo

Transcript

Ex 7.3,3 Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of PQR (see figure ).Show that : ABM PQN Given: AB = PQ BC = QR & AM = PN Also, AM is the median of ABC So, BM = CM = 1/2 BC Also, PN is the median of PQR So, QN = RN = 1/2 QR To prove: ABM PQN Proof Since BC = QR 1/2 BC = 1/2 QR BM = QN In ABM & PQN AB = PQ AM = PN BM = QN So, ABM PQN Ex 7.3,3 Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of PQR (see figure ).Show that : (ii) ABC PQR From part (i), ABM PQN B= Q In ABC & PQR AB = PQ B= Q BC = QR So, ABC PQR

Chapter 7 Class 9 Triangles

Class 9

Important Questions for Exam - Class 9

- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
- Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.