Chapter 7 Class 9 Triangles
Ex 7.1, 3 Important
Ex 7.1, 5 Important
Ex 7.1, 7 Important
Ex 7.1, 8 Important
Example 6 Important
Ex 7.2, 4 Important
Ex 7.2, 6 Important
Example 8 Important
Ex 7.3, 3 Important
Ex 7.3, 5 Important
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Chapter 7 Class 9 Triangles
Last updated at April 16, 2024 by Teachoo
Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved