Last updated at June 29, 2018 by Teachoo

Transcript

Ex 7.3,5 ABC is an isosceles triangle with AB = AC . Draw AP ⊥ BC to show that ∠𝐵 = ∠𝐶. Given: Since ∆ ABC is isosceles AB = AC Given AP ⊥ BC , So, ∠APB = ∠APC = 90∘ To prove: ∠ B = ∠ C Proof: In ∆ABP and ∆ACP ∠APB = ∠APC = 90∘ AB = AC AP = AP ∆ ABP ≅ ∆ ACP So, ∠B = ∠C Hence proved

Chapter 7 Class 9 Triangles

Class 9

Important Questions for Exam - Class 9

- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
- Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.