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Ex 7.2, 5 - ABC and DBC are two isosceles triangles on same - SSS

Ex 7.2, 5 - Chapter 7 Class 9 Triangles - Part 2

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Ex7.2, 5 ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that ∠ABD = ∠ACD. Given: ΔABC is isosceles So, AB = AC ΔDBC is isosceles So, DB = DC To prove: ∠ ABD = ∠ ACD Proof Let us join AD. We take ΔABD and ΔACD, In ΔABD and ΔACD, AB = AC BD = CD AD = AD ∴ ΔABD ≅ ΔACD ⇒∠ABD = ∠ACD Hence proved

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