Ex 7.2, 5 - ABC and DBC are two isosceles triangles on same - SSS

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Ex 7.2, 5 - Chapter 7 Class 9 Triangles - Part 2

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  1. Chapter 7 Class 9 Triangles (Term 1)
  2. Serial order wise

Transcript

Ex7.2, 5 ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that ∠ABD = ∠ACD. Given: ΔABC is isosceles So, AB = AC ΔDBC is isosceles So, DB = DC To prove: ∠ ABD = ∠ ACD Proof Let us join AD. We take ΔABD and ΔACD, In ΔABD and ΔACD, AB = AC BD = CD AD = AD ∴ ΔABD ≅ ΔACD ⇒∠ABD = ∠ACD Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.