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Ex7.2, 3 ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see the given figure). Show that these altitudes are equal. Given: Given ABC is isosceles with AB & AC equal, i.e. AB = AC BE and CF are altitudes. So, AEB = 90 and AFC = 90 To prove: BE = CF Proof: We take ABE and ACF, In ABE and ACF, AEB = AFC A = A AB = AC ABE ACF BE = CF Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.